Author: program45_-rt8nb

Below program will accept the range for example 62 to 70. Program will count all even and odd numbers from range 62 to 70 and perform sum of even and odd numbers respectively. It also provide average of odd and even numbers.

// Program Name: Accept Range from user and then find even odd numbers with sum and average respectively.
#include<stdio.h>
 
void main()
{
 int startNum=0,endNum=0,i=0,eNoCnt=0,oNoCnt=0,eSum=0,oSum=0;
 
 printf("\n\t Provide Range of number to identify even number as requested for e.g 56 90");
 printf("\n\n\n\t Please provide Range\t");
 scanf("%d", &startNum);
 scanf("%d", &endNum);

 for(i = startNum; i < endNum; i ++)
 {
   if(i % 2 == 0)
   {
     eNoCnt++;
     eSum=eSum+i;
   }
   else
   {
     oNoCnt++;
     oSum=oSum+i;
   }
 }
  
 printf("\n\t Total Number of Even Numbers are = %d ", eNoCnt);
 printf("\n\t Total of Even number is %d",eSum);
 printf("\n\t Average of Even Number is %d",eSum/eNoCnt);
 printf("\n\n\t Total Number of Odd Numbers are = %d ", oNoCnt);
 printf("\n\t Total of Odd number is %d",oSum);
 printf("\n\t Average of Odd Number is %d",oSum/oNoCnt);
}

Output

Please provide Range   1
500

         Total Number of Even Numbers are = 249 
         Total of Even number is 62250
         Average of Even Number is 250

         Total Number of Odd Numbers are = 250 
         Total of Odd number is 62500
         Average of Odd Number is 250

//Program Name: To find length of the string with and without function.

#include<stdio.h>
#include<string.h>
void main()
{
char str[250]; //to store entered string
int cnt;  //counter

printf("\n\tEnter a string to check length:" );
gets(str);

for(cnt = 0; str[cnt] != '\0'; ++cnt);

printf("\n\t Length of string without using function: %d", cnt);

printf("\n\t Length of string with strlen function %d",strlen(str));

}

Output

Enter a string to check length:Learning C
Length of string without using function: 10
	 Length of string with strlen function 10

Below program will first accept total number which user want to enter. Then user has to enter numbers one by one.

Program will identify even and Odd numbers and store their total count in variable.

// Program Name: Accept n numbers from user and then identify even or odd Numbers
#include<stdio.h>
 
void main()
{
 int totalNum, i, ary[100];
 int eNoCnt = 0, oNoCnt = 0;
 
 printf("\n\t Enter the Size of an Array (total numbers)  :  \t");
 scanf("%d", &totalNum);
 
 printf("\n\t Enter the Numbers to identify even numbers\t");
 for(i = 0; i < totalNum; i++)
 {
   scanf("%d", &ary[i]);
 }
  
 for(i = 0; i < totalNum; i ++)
 {
   if(ary[i] % 2 == 0)
   {
     eNoCnt++;
   }
   else
   {
     oNoCnt++;
   }
 }
  
 printf("\n\t Total Number of Even Numbers are = %d ", eNoCnt);
 printf("\n\t Total Number of Odd Numbers are = %d ", oNoCnt);
}

	 Enter the Size of an Array (total numbers)  :  	6



	 Enter the Numbers to identify even numbers	1

2

3

4

5

6



	 Total Number of Even Numbers are = 3 

	 Total Number of Odd Numbers are = 3 

Program to print Odd Numbers till user input

// Program to print odd numbers from 1 to n
#include <stdio.h>
int main() {
    int range;
    printf("Enter range of number to print odd numbers");
    scanf("%d",&range);
      printf("Odd Numbers from 1 to %d are \n",range);
    for(int i =1;i<=range;i++)
    {
        if (i%2 != 0)
        printf("\t%d",i);
    }
    return 0;
}

Output

Enter range of number to print odd numbers   15
Odd Numbers from 1 to 15 are 
	1	3	5	7	9	11	13	15

Program to Print Even Numbers till User Input

// Program to print even numbers from 1 to n
#include <stdio.h>
int main() {
    int range;
    printf("Enter range of number to print even numbers  ");
    scanf("%d",&range);
      printf("Even numbers from  1 to %d are \n",range);
    for(int i =1;i<=range;i++)
    {
        if (i%2 ==  0)
        printf("\t%d",i);
    }
    return 0;
}

Output

Enter range of number to print even numbers  15
Even numbers from  1 to 15 are 
	2	4	6	8	10	12	14

This program will accept input from user. and then by iterating each character from sentence it will count number of vowel and consonant. “A”, “E”,”I”,”O”,”U” either in upper or lower case character are vowels. Other than “A”, “E”,”I”,”O”,”U” all characters between A to Z are consonant.

//Program Name: C Program to count vowel, consonant 

#include<stdio.h>
#include<string.h>
 void main()
 {
   char str[50],ch; //defining variable to accept input
   int chCount=0,cCnt=0,vCount=0;

    printf("\n\tEnter string to count vowel, consonant:\t");
    gets(str); // Read input in "str" variable
    

  while (str[chCount] != '\0')
  {
      ch=str[chCount];
      
   if((ch >= 'a' && ch <= 'z') || (ch >= 'A' &&ch <= 'Z'))
   {
       if(ch=='a'||ch=='i'||ch=='o'||ch=='u'||ch=='e' ||ch=='A'||ch=='E'||ch=='I'||ch=='O'||ch=='U')
	       vCount=vCount+1;
	    else
	       cCnt=cCnt+1;
   }
    chCount++;
 }

 printf("\nNumber of vowels in given sentence are :%d \t ",vCount);
 printf("\nNumber of Consonants in given sentence are : %d \t ",cCnt);
 }

Output

Program will read sentence in variable str. Every sentence end with ‘\0’ so we are iterating sentence character by character till we not receive ‘\0’. as we need to increment while count manually hence we are using chCount++; Each character is then getting compared with vowels and then associated variable counter is also getting incremented by one.

Click here for another program for vowel and consonants https://ethosspace.com/programmers/c-program-to-check-if-vowel-or-consonant/